Base | Representation |
---|---|
bin | 1101000001000110011000… |
… | …0111101000000010101001 |
3 | 1212200021011211011201101102 |
4 | 3100101212013220002221 |
5 | 3333444042320232241 |
6 | 50235031520131145 |
7 | 3005022122202563 |
oct | 320214607500251 |
9 | 55607154151342 |
10 | 14312544305321 |
11 | 4618a09151169 |
12 | 1731a4a166ab5 |
13 | 7ca889912812 |
14 | 376a335d8333 |
15 | 19c47e9e839b |
hex | d04661e80a9 |
14312544305321 has 8 divisors (see below), whose sum is σ = 14774907512064. Its totient is φ = 13850222862960.
The previous prime is 14312544305309. The next prime is 14312544305327. The reversal of 14312544305321 is 12350344521341.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 14312544305321 - 214 = 14312544288937 is a prime.
It is not an unprimeable number, because it can be changed into a prime (14312544305327) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 9743891 + ... + 11116136.
It is an arithmetic number, because the mean of its divisors is an integer number (1846863439008).
Almost surely, 214312544305321 is an apocalyptic number.
It is an amenable number.
14312544305321 is a deficient number, since it is larger than the sum of its proper divisors (462363206743).
14312544305321 is a wasteful number, since it uses less digits than its factorization.
14312544305321 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 20882191.
The product of its (nonzero) digits is 172800, while the sum is 38.
Adding to 14312544305321 its reverse (12350344521341), we get a palindrome (26662888826662).
The spelling of 14312544305321 in words is "fourteen trillion, three hundred twelve billion, five hundred forty-four million, three hundred five thousand, three hundred twenty-one".
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