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143126223551249 is a prime number
BaseRepresentation
bin100000100010110000101011…
…101101100111101100010001
3200202202201210121101120212212
4200202300223231213230101
5122224440001212114444
61224223140203201505
742101346150030641
oct4042605355475421
9622681717346785
10143126223551249
11416715439a1224
12140769a2816295
1361b298b905663
14274b4bbccc521
15118309527b19e
hex822c2bb67b11

143126223551249 has 2 divisors, whose sum is σ = 143126223551250. Its totient is φ = 143126223551248.

The previous prime is 143126223551243. The next prime is 143126223551281. The reversal of 143126223551249 is 942155322621341.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 82083020161024 + 61043203390225 = 9059968^2 + 7813015^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-143126223551249 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 143126223551197 and 143126223551206.

It is not a weakly prime, because it can be changed into another prime (143126223551243) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 71563111775624 + 71563111775625.

It is an arithmetic number, because the mean of its divisors is an integer number (71563111775625).

Almost surely, 2143126223551249 is an apocalyptic number.

It is an amenable number.

143126223551249 is a deficient number, since it is larger than the sum of its proper divisors (1).

143126223551249 is an equidigital number, since it uses as much as digits as its factorization.

143126223551249 is an evil number, because the sum of its binary digits is even.

The product of its digits is 3110400, while the sum is 50.

The spelling of 143126223551249 in words is "one hundred forty-three trillion, one hundred twenty-six billion, two hundred twenty-three million, five hundred fifty-one thousand, two hundred forty-nine".