Base | Representation |
---|---|
bin | 1000010101001101000… |
… | …1100011001001100001 |
3 | 111200110001021200121110 |
4 | 2011103101203021201 |
5 | 4321113020430423 |
6 | 145430430413533 |
7 | 13224630452661 |
oct | 2052321431141 |
9 | 450401250543 |
10 | 143131030113 |
11 | 5577980a435 |
12 | 238a63612a9 |
13 | 10660462b36 |
14 | 6cdb3c21a1 |
15 | 3acaa49193 |
hex | 2153463261 |
143131030113 has 8 divisors (see below), whose sum is σ = 191089544800. Its totient is φ = 95296601088.
The previous prime is 143131030061. The next prime is 143131030123. The reversal of 143131030113 is 311030131341.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 143131030113 - 213 = 143131021921 is a prime.
It is a Duffinian number.
It is a self number, because there is not a number n which added to its sum of digits gives 143131030113.
It is not an unprimeable number, because it can be changed into a prime (143131030123) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 31018723 + ... + 31023336.
It is an arithmetic number, because the mean of its divisors is an integer number (23886193100).
Almost surely, 2143131030113 is an apocalyptic number.
It is an amenable number.
143131030113 is a deficient number, since it is larger than the sum of its proper divisors (47958514687).
143131030113 is an equidigital number, since it uses as much as digits as its factorization.
143131030113 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 62042831.
The product of its (nonzero) digits is 324, while the sum is 21.
Adding to 143131030113 its reverse (311030131341), we get a palindrome (454161161454).
The spelling of 143131030113 in words is "one hundred forty-three billion, one hundred thirty-one million, thirty thousand, one hundred thirteen".
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