Base | Representation |
---|---|
bin | 100000100010110101101000… |
… | …010010011011100011001111 |
3 | 200202210020111202110000222102 |
4 | 200202311220102123203033 |
5 | 122230031340402113403 |
6 | 1224225415213505315 |
7 | 42101624601641252 |
oct | 4042655022334317 |
9 | 622706452400872 |
10 | 143131534801103 |
11 | 41673819a66912 |
12 | 14077a254a223b |
13 | 61b33270a0754 |
14 | 274b863451099 |
15 | 11832a66b4b88 |
hex | 822d6849b8cf |
143131534801103 has 2 divisors, whose sum is σ = 143131534801104. Its totient is φ = 143131534801102.
The previous prime is 143131534801049. The next prime is 143131534801139. The reversal of 143131534801103 is 301108435131341.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 143131534801103 - 28 = 143131534800847 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (143131534800103) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 71565767400551 + 71565767400552.
It is an arithmetic number, because the mean of its divisors is an integer number (71565767400552).
Almost surely, 2143131534801103 is an apocalyptic number.
143131534801103 is a deficient number, since it is larger than the sum of its proper divisors (1).
143131534801103 is an equidigital number, since it uses as much as digits as its factorization.
143131534801103 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 51840, while the sum is 38.
Adding to 143131534801103 its reverse (301108435131341), we get a palindrome (444239969932444).
The spelling of 143131534801103 in words is "one hundred forty-three trillion, one hundred thirty-one billion, five hundred thirty-four million, eight hundred one thousand, one hundred three".
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