Base | Representation |
---|---|
bin | 100000100010110110000101… |
… | …010001010001010110100010 |
3 | 200202210021202122101100110222 |
4 | 200202312011101101112202 |
5 | 122230033334341131300 |
6 | 1224225535343323042 |
7 | 42101642624606105 |
oct | 4042660521212642 |
9 | 622707678340428 |
10 | 143132021036450 |
11 | 41673a49481706 |
12 | 14077b402b0482 |
13 | 61b33a3a46584 |
14 | 274b8abc6273c |
15 | 11832d420e785 |
hex | 822d854515a2 |
143132021036450 has 24 divisors (see below), whose sum is σ = 266430821823012. Its totient is φ = 57208665899520.
The previous prime is 143132021036449. The next prime is 143132021036461. The reversal of 143132021036450 is 54630120231341.
It can be written as a sum of positive squares in 6 ways, for example, as 115621482024049 + 27510539012401 = 10752743^2 + 5245049^2 .
It is a self number, because there is not a number n which added to its sum of digits gives 143132021036450.
It is an unprimeable number.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 1103497379 + ... + 1103627078.
Almost surely, 2143132021036450 is an apocalyptic number.
143132021036450 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
143132021036450 is a deficient number, since it is larger than the sum of its proper divisors (123298800786562).
143132021036450 is a wasteful number, since it uses less digits than its factorization.
143132021036450 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2207125766 (or 2207125761 counting only the distinct ones).
The product of its (nonzero) digits is 51840, while the sum is 35.
Adding to 143132021036450 its reverse (54630120231341), we get a palindrome (197762141267791).
The spelling of 143132021036450 in words is "one hundred forty-three trillion, one hundred thirty-two billion, twenty-one million, thirty-six thousand, four hundred fifty".
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