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143132213406103 is a prime number
BaseRepresentation
bin100000100010110110010000…
…101111000110100110010111
3200202210022021001100202000221
4200202312100233012212113
5122230034233112443403
61224230010414415211
742101650451663425
oct4042662057064627
9622708231322027
10143132213406103
1141674038022899
1214077b94801507
1361b340485b77c
14274b8c961a115
1511832e605cdbd
hex822d90bc6997

143132213406103 has 2 divisors, whose sum is σ = 143132213406104. Its totient is φ = 143132213406102.

The previous prime is 143132213406053. The next prime is 143132213406263. The reversal of 143132213406103 is 301604312231341.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 143132213406103 - 29 = 143132213405591 is a prime.

It is a super-2 number, since 2×1431322134061032 (a number of 29 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (143132213406703) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 71566106703051 + 71566106703052.

It is an arithmetic number, because the mean of its divisors is an integer number (71566106703052).

Almost surely, 2143132213406103 is an apocalyptic number.

143132213406103 is a deficient number, since it is larger than the sum of its proper divisors (1).

143132213406103 is an equidigital number, since it uses as much as digits as its factorization.

143132213406103 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 31104, while the sum is 34.

Adding to 143132213406103 its reverse (301604312231341), we get a palindrome (444736525637444).

The spelling of 143132213406103 in words is "one hundred forty-three trillion, one hundred thirty-two billion, two hundred thirteen million, four hundred six thousand, one hundred three".