Base | Representation |
---|---|
bin | 100000100010110110010000… |
… | …101111000110100110010111 |
3 | 200202210022021001100202000221 |
4 | 200202312100233012212113 |
5 | 122230034233112443403 |
6 | 1224230010414415211 |
7 | 42101650451663425 |
oct | 4042662057064627 |
9 | 622708231322027 |
10 | 143132213406103 |
11 | 41674038022899 |
12 | 14077b94801507 |
13 | 61b340485b77c |
14 | 274b8c961a115 |
15 | 11832e605cdbd |
hex | 822d90bc6997 |
143132213406103 has 2 divisors, whose sum is σ = 143132213406104. Its totient is φ = 143132213406102.
The previous prime is 143132213406053. The next prime is 143132213406263. The reversal of 143132213406103 is 301604312231341.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 143132213406103 - 29 = 143132213405591 is a prime.
It is a super-2 number, since 2×1431322134061032 (a number of 29 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (143132213406703) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 71566106703051 + 71566106703052.
It is an arithmetic number, because the mean of its divisors is an integer number (71566106703052).
Almost surely, 2143132213406103 is an apocalyptic number.
143132213406103 is a deficient number, since it is larger than the sum of its proper divisors (1).
143132213406103 is an equidigital number, since it uses as much as digits as its factorization.
143132213406103 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 31104, while the sum is 34.
Adding to 143132213406103 its reverse (301604312231341), we get a palindrome (444736525637444).
The spelling of 143132213406103 in words is "one hundred forty-three trillion, one hundred thirty-two billion, two hundred thirteen million, four hundred six thousand, one hundred three".
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