Base | Representation |
---|---|
bin | 10100110101000001101… |
… | …100011000000000101011 |
3 | 12001211111120212202022112 |
4 | 110311001230120000223 |
5 | 141422324010330131 |
6 | 3013313041112535 |
7 | 205260412323623 |
oct | 24650154300053 |
9 | 5054446782275 |
10 | 1431326261291 |
11 | 5020273a6033 |
12 | 1b149832874b |
13 | a4c869a0264 |
14 | 4d3c2c4d883 |
15 | 2737341502b |
hex | 14d41b1802b |
1431326261291 has 2 divisors, whose sum is σ = 1431326261292. Its totient is φ = 1431326261290.
The previous prime is 1431326261263. The next prime is 1431326261341. The reversal of 1431326261291 is 1921626231341.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1431326261291 - 210 = 1431326260267 is a prime.
It is a super-2 number, since 2×14313262612912 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (1431326261251) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 715663130645 + 715663130646.
It is an arithmetic number, because the mean of its divisors is an integer number (715663130646).
Almost surely, 21431326261291 is an apocalyptic number.
1431326261291 is a deficient number, since it is larger than the sum of its proper divisors (1).
1431326261291 is an equidigital number, since it uses as much as digits as its factorization.
1431326261291 is an evil number, because the sum of its binary digits is even.
The product of its digits is 93312, while the sum is 41.
The spelling of 1431326261291 in words is "one trillion, four hundred thirty-one billion, three hundred twenty-six million, two hundred sixty-one thousand, two hundred ninety-one".
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