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14313340420123 = 23679288345503
BaseRepresentation
bin1101000001001001010110…
…0100100100000000011011
31212200100020022012112120211
43100102111210210000123
53334002210121420443
650235242515431551
73005050630105153
oct320222544440033
955610208175524
1014313340420123
114619287578a88
1217320308b55b7
137ca985835174
14376aab231763
1519c4c985419d
hexd049592401b

14313340420123 has 8 divisors (see below), whose sum is σ = 15158579862528. Its totient is φ = 13486677668904.

The previous prime is 14313340420087. The next prime is 14313340420157. The reversal of 14313340420123 is 32102404331341.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 14313340420123 - 237 = 14175901466651 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (14313340426123) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 4644171211 + ... + 4644174292.

It is an arithmetic number, because the mean of its divisors is an integer number (1894822482816).

Almost surely, 214313340420123 is an apocalyptic number.

14313340420123 is a deficient number, since it is larger than the sum of its proper divisors (845239442405).

14313340420123 is an equidigital number, since it uses as much as digits as its factorization.

14313340420123 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 9288345593.

The product of its (nonzero) digits is 20736, while the sum is 31.

Adding to 14313340420123 its reverse (32102404331341), we get a palindrome (46415744751464).

The spelling of 14313340420123 in words is "fourteen trillion, three hundred thirteen billion, three hundred forty million, four hundred twenty thousand, one hundred twenty-three".

Divisors: 1 23 67 1541 9288345503 213631946569 622319148701 14313340420123