14313353441 has 2 divisors, whose sum is σ = 14313353442. Its totient is φ = 14313353440.

The previous prime is 14313353437. The next prime is 14313353443. The reversal of 14313353441 is 14435331341.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 7956640000 + 6356713441 = 89200^2 + 79729^2 .

It is a cyclic number.

It is not a de Polignac number, because 14313353441 - 2² = 14313353437 is a prime.

Together with 14313353443, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 14313353398 and 14313353407.

It is not a weakly prime, because it can be changed into another prime (14313353443) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7156676720 + 7156676721.

It is an arithmetic number, because the mean of its divisors is an integer number (7156676721).

Almost surely, 2^14313353441 is an apocalyptic number.

It is an amenable number.

14313353441 is a deficient number, since it is larger than the sum of its proper divisors (1).

14313353441 is an equidigital number, since it uses as much as digits as its factorization.

14313353441 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 25920, while the sum is 32.

Adding to 14313353441 its reverse (14435331341), we get a palindrome (28748684782).

The spelling of 14313353441 in words is "fourteen billion, three hundred thirteen million, three hundred fifty-three thousand, four hundred forty-one".