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14313355041 = 312737567861
BaseRepresentation
bin11010101010010010…
…00111011100100001
31100221112002202212210
431111021013130201
5213303204330131
610324144512333
71014461340036
oct152511073441
940845082783
1014313355041
116085574547
12293561b6a9
13147150466b
1499ad6538d
1558b8ce146
hex355247721

14313355041 has 8 divisors (see below), whose sum is σ = 19234745344. Its totient is φ = 9467100720.

The previous prime is 14313355039. The next prime is 14313355057. The reversal of 14313355041 is 14055331341.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 14313355041 - 21 = 14313355039 is a prime.

It is a super-2 number, since 2×143133550412 (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is a Curzon number.

It is not an unprimeable number, because it can be changed into a prime (14313355541) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 18783550 + ... + 18784311.

It is an arithmetic number, because the mean of its divisors is an integer number (2404343168).

Almost surely, 214313355041 is an apocalyptic number.

It is an amenable number.

14313355041 is a deficient number, since it is larger than the sum of its proper divisors (4921390303).

14313355041 is a wasteful number, since it uses less digits than its factorization.

14313355041 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 37567991.

The product of its (nonzero) digits is 10800, while the sum is 30.

Adding to 14313355041 its reverse (14055331341), we get a palindrome (28368686382).

The spelling of 14313355041 in words is "fourteen billion, three hundred thirteen million, three hundred fifty-five thousand, forty-one".

Divisors: 1 3 127 381 37567861 112703583 4771118347 14313355041