Base | Representation |
---|---|
bin | 1101000001001001100111… |
… | …0101000100011101110011 |
3 | 1212200100102021121212112001 |
4 | 3100102121311010131303 |
5 | 3334002331413344433 |
6 | 50235253550514431 |
7 | 3005052455232553 |
oct | 320223165043563 |
9 | 55610367555461 |
10 | 14313411856243 |
11 | 461931392aaa5 |
12 | 1732050805a17 |
13 | 7ca997587566 |
14 | 376ab6909163 |
15 | 19c4d0c6557d |
hex | d0499d44773 |
14313411856243 has 2 divisors, whose sum is σ = 14313411856244. Its totient is φ = 14313411856242.
The previous prime is 14313411856111. The next prime is 14313411856301. The reversal of 14313411856243 is 34265811431341.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-14313411856243 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 14313411856193 and 14313411856202.
It is not a weakly prime, because it can be changed into another prime (14313411856643) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7156705928121 + 7156705928122.
It is an arithmetic number, because the mean of its divisors is an integer number (7156705928122).
Almost surely, 214313411856243 is an apocalyptic number.
14313411856243 is a deficient number, since it is larger than the sum of its proper divisors (1).
14313411856243 is an equidigital number, since it uses as much as digits as its factorization.
14313411856243 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 829440, while the sum is 46.
The spelling of 14313411856243 in words is "fourteen trillion, three hundred thirteen billion, four hundred eleven million, eight hundred fifty-six thousand, two hundred forty-three".
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