Base | Representation |
---|---|
bin | 1000010101001101110… |
… | …1010101100001100111 |
3 | 111200110021002200012011 |
4 | 2011103131111201213 |
5 | 4321114313320124 |
6 | 145431020535051 |
7 | 13224665642341 |
oct | 2052335254147 |
9 | 450407080164 |
10 | 143134120039 |
11 | 5578052a999 |
12 | 238a73b1487 |
13 | 10660ca53b1 |
14 | 6cdb988291 |
15 | 3acae59994 |
hex | 2153755867 |
143134120039 has 2 divisors, whose sum is σ = 143134120040. Its totient is φ = 143134120038.
The previous prime is 143134120033. The next prime is 143134120043. The reversal of 143134120039 is 930021431341.
143134120039 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 143134120039 - 27 = 143134119911 is a prime.
It is a super-2 number, since 2×1431341200392 (a number of 23 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (143134120033) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 71567060019 + 71567060020.
It is an arithmetic number, because the mean of its divisors is an integer number (71567060020).
Almost surely, 2143134120039 is an apocalyptic number.
143134120039 is a deficient number, since it is larger than the sum of its proper divisors (1).
143134120039 is an equidigital number, since it uses as much as digits as its factorization.
143134120039 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 7776, while the sum is 31.
The spelling of 143134120039 in words is "one hundred forty-three billion, one hundred thirty-four million, one hundred twenty thousand, thirty-nine".
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