Base | Representation |
---|---|
bin | 1101000001001001100111… |
… | …0110000010100000010011 |
3 | 1212200100102022002210002121 |
4 | 3100102121312002200103 |
5 | 3334002332000012410 |
6 | 50235254000155111 |
7 | 3005052460341451 |
oct | 320223166024023 |
9 | 55610368083077 |
10 | 14313412110355 |
11 | 4619313a93a06 |
12 | 1732050908a97 |
13 | 7ca997646117 |
14 | 376ab69739d1 |
15 | 19c4d0cb59da |
hex | d0499d82813 |
14313412110355 has 16 divisors (see below), whose sum is σ = 17338096189440. Its totient is φ = 11343007301472.
The previous prime is 14313412110343. The next prime is 14313412110467. The reversal of 14313412110355 is 55301121431341.
It is a cyclic number.
It is not a de Polignac number, because 14313412110355 - 213 = 14313412102163 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 14313412110355.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 17008635 + ... + 17830324.
It is an arithmetic number, because the mean of its divisors is an integer number (1083631011840).
Almost surely, 214313412110355 is an apocalyptic number.
14313412110355 is a deficient number, since it is larger than the sum of its proper divisors (3024684079085).
14313412110355 is a wasteful number, since it uses less digits than its factorization.
14313412110355 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 34839738.
The product of its (nonzero) digits is 21600, while the sum is 34.
Adding to 14313412110355 its reverse (55301121431341), we get a palindrome (69614533541696).
The spelling of 14313412110355 in words is "fourteen trillion, three hundred thirteen billion, four hundred twelve million, one hundred ten thousand, three hundred fifty-five".
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