1431341401203 has 64 divisors (see below), whose sum is σ = 2490378992640. Its totient is φ = 795441772800.

The previous prime is 1431341401201. The next prime is 1431341401207. The reversal of 1431341401203 is 3021041431341.

1431341401203 is a `hidden beast` number, since 1 + 4 + 3 + 13 + 41 + 401 + 203 = 666.

It is not a de Polignac number, because 1431341401203 - 2¹ = 1431341401201 is a prime.

It is a Harshad number since it is a multiple of its sum of digits (27).

It is not an unprimeable number, because it can be changed into a prime (1431341401201) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 2165088 + ... + 2747778.

It is an arithmetic number, because the mean of its divisors is an integer number (38912171760).

Almost surely, 2^{1431341401203} is an apocalyptic number.

1431341401203 is a deficient number, since it is larger than the sum of its proper divisors (1059037591437).

1431341401203 is a wasteful number, since it uses less digits than its factorization.

1431341401203 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 583065 (or 583059 counting only the distinct ones).

The product of its (nonzero) digits is 3456, while the sum is 27.

Adding to 1431341401203 its reverse (3021041431341), we get a palindrome (4452382832544).

The spelling of 1431341401203 in words is "one trillion, four hundred thirty-one billion, three hundred forty-one million, four hundred one thousand, two hundred three".