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14313422023 is a prime number
BaseRepresentation
bin11010101010010010…
…10111110011000111
31100221112020011202121
431111021113303013
5213303214001043
610324150150411
71014462036235
oct152511276307
940845204677
1014313422023
11608560a8aa
122935652407
131471528cb4
1499ad81955
1558b8e3ded
hex355257cc7

14313422023 has 2 divisors, whose sum is σ = 14313422024. Its totient is φ = 14313422022.

The previous prime is 14313422009. The next prime is 14313422041. The reversal of 14313422023 is 32022431341.

It is a weak prime.

It is an emirp because it is prime and its reverse (32022431341) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 14313422023 - 217 = 14313290951 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (14313422423) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7156711011 + 7156711012.

It is an arithmetic number, because the mean of its divisors is an integer number (7156711012).

Almost surely, 214313422023 is an apocalyptic number.

14313422023 is a deficient number, since it is larger than the sum of its proper divisors (1).

14313422023 is an equidigital number, since it uses as much as digits as its factorization.

14313422023 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 3456, while the sum is 25.

Adding to 14313422023 its reverse (32022431341), we get a palindrome (46335853364).

The spelling of 14313422023 in words is "fourteen billion, three hundred thirteen million, four hundred twenty-two thousand, twenty-three".