Base | Representation |
---|---|
bin | 10100110101000010101… |
… | …101110000010010111010 |
3 | 12001211112210010111101001 |
4 | 110311002231300102322 |
5 | 141422342402300442 |
6 | 3013314452315214 |
7 | 205261011105226 |
oct | 24650255602272 |
9 | 5054483114331 |
10 | 1431343400122 |
11 | 502036041759 |
12 | 1b14a2012b0a |
13 | a4c8a3c128c |
14 | 4d3c5231786 |
15 | 27374b9d2b7 |
hex | 14d42b704ba |
1431343400122 has 4 divisors (see below), whose sum is σ = 2147015100186. Its totient is φ = 715671700060.
The previous prime is 1431343400099. The next prime is 1431343400141. The reversal of 1431343400122 is 2210043431341.
It is a happy number.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 785813104521 + 645530295601 = 886461^2 + 803449^2 .
It is a super-2 number, since 2×14313434001222 (a number of 25 digits) contains 22 as substring.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 357835850029 + ... + 357835850032.
Almost surely, 21431343400122 is an apocalyptic number.
1431343400122 is a deficient number, since it is larger than the sum of its proper divisors (715671700064).
1431343400122 is an equidigital number, since it uses as much as digits as its factorization.
1431343400122 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 715671700063.
The product of its (nonzero) digits is 6912, while the sum is 28.
Adding to 1431343400122 its reverse (2210043431341), we get a palindrome (3641386831463).
The spelling of 1431343400122 in words is "one trillion, four hundred thirty-one billion, three hundred forty-three million, four hundred thousand, one hundred twenty-two".
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