Base | Representation |
---|---|
bin | 1101000001001001101100… |
… | …1001100010111101001011 |
3 | 1212200100110211021221201122 |
4 | 3100102123021202331023 |
5 | 3334002403101014402 |
6 | 50235300101305455 |
7 | 3005053144404314 |
oct | 320223311427513 |
9 | 55610424257648 |
10 | 14313434001227 |
11 | 4619325385939 |
12 | 173205810528b |
13 | 7ca99c03c0ba |
14 | 376ab983160b |
15 | 19c4d2b8bca2 |
hex | d049b262f4b |
14313434001227 has 2 divisors, whose sum is σ = 14313434001228. Its totient is φ = 14313434001226.
The previous prime is 14313434001199. The next prime is 14313434001247. The reversal of 14313434001227 is 72210043431341.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 14313434001227 - 228 = 14313165565771 is a prime.
It is not a weakly prime, because it can be changed into another prime (14313434001247) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7156717000613 + 7156717000614.
It is an arithmetic number, because the mean of its divisors is an integer number (7156717000614).
Almost surely, 214313434001227 is an apocalyptic number.
14313434001227 is a deficient number, since it is larger than the sum of its proper divisors (1).
14313434001227 is an equidigital number, since it uses as much as digits as its factorization.
14313434001227 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 48384, while the sum is 35.
Adding to 14313434001227 its reverse (72210043431341), we get a palindrome (86523477432568).
The spelling of 14313434001227 in words is "fourteen trillion, three hundred thirteen billion, four hundred thirty-four million, one thousand, two hundred twenty-seven".
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