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14313434001199 is a prime number
BaseRepresentation
bin1101000001001001101100…
…1001100010111100101111
31212200100110211021221200121
43100102123021202330233
53334002403101014244
650235300101305411
73005053144404244
oct320223311427457
955610424257617
1014313434001199
114619325385913
121732058105267
137ca99c03c098
14376ab98315cb
1519c4d2b8bc84
hexd049b262f2f

14313434001199 has 2 divisors, whose sum is σ = 14313434001200. Its totient is φ = 14313434001198.

The previous prime is 14313434001161. The next prime is 14313434001227. The reversal of 14313434001199 is 99110043431341.

14313434001199 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 14313434001199 - 233 = 14304844066607 is a prime.

It is a super-2 number, since 2×143134340011992 (a number of 27 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (14313434001109) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7156717000599 + 7156717000600.

It is an arithmetic number, because the mean of its divisors is an integer number (7156717000600).

Almost surely, 214313434001199 is an apocalyptic number.

14313434001199 is a deficient number, since it is larger than the sum of its proper divisors (1).

14313434001199 is an equidigital number, since it uses as much as digits as its factorization.

14313434001199 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 139968, while the sum is 43.

The spelling of 14313434001199 in words is "fourteen trillion, three hundred thirteen billion, four hundred thirty-four million, one thousand, one hundred ninety-nine".