Base | Representation |
---|---|
bin | 100000100010111000111010… |
… | …000111010110111110000001 |
3 | 200202210120121002112110120202 |
4 | 200202320322013112332001 |
5 | 122230111043102122423 |
6 | 1224231200410214545 |
7 | 42102111046052426 |
oct | 4042707207267601 |
9 | 622716532473522 |
10 | 143135055114113 |
11 | 416752660a8107 |
12 | 14078648424455 |
13 | 61b37684ccaba |
14 | 274bab8bb9d4d |
15 | 1183410785728 |
hex | 822e3a1d6f81 |
143135055114113 has 8 divisors (see below), whose sum is σ = 150754190516928. Its totient is φ = 135632242389424.
The previous prime is 143135055114097. The next prime is 143135055114131. The reversal of 143135055114113 is 311411550531341.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 143135055114113 - 24 = 143135055114097 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (143135055116113) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 29080667006 + ... + 29080671927.
It is an arithmetic number, because the mean of its divisors is an integer number (18844273814616).
Almost surely, 2143135055114113 is an apocalyptic number.
It is an amenable number.
143135055114113 is a deficient number, since it is larger than the sum of its proper divisors (7619135402815).
143135055114113 is a wasteful number, since it uses less digits than its factorization.
143135055114113 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 58161339063.
The product of its (nonzero) digits is 54000, while the sum is 38.
The spelling of 143135055114113 in words is "one hundred forty-three trillion, one hundred thirty-five billion, fifty-five million, one hundred fourteen thousand, one hundred thirteen".
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