143135145503 has 4 divisors (see below), whose sum is σ = 163583023440. Its totient is φ = 122687267568.

The previous prime is 143135145499. The next prime is 143135145523. The reversal of 143135145503 is 305541531341.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 143135145503 - 2² = 143135145499 is a prime.

It is a super-2 number, since 2×143135145503² (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (143135145523) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 10223938958 + ... + 10223938971.

It is an arithmetic number, because the mean of its divisors is an integer number (40895755860).

Almost surely, 2^143135145503 is an apocalyptic number.

143135145503 is a deficient number, since it is larger than the sum of its proper divisors (20447877937).

143135145503 is an equidigital number, since it uses as much as digits as its factorization.

143135145503 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 20447877936.

The product of its (nonzero) digits is 54000, while the sum is 35.

Adding to 143135145503 its reverse (305541531341), we get a palindrome (448676676844).

The spelling of 143135145503 in words is "one hundred forty-three billion, one hundred thirty-five million, one hundred forty-five thousand, five hundred three".