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1431352001341 is a prime number
BaseRepresentation
bin10100110101000011001…
…110100100001100111101
312001211120101022111000201
4110311003032210030331
5141422402103020331
63013315400523501
7205261144160533
oct24650316441475
95054511274021
101431352001341
1150203a9869a9
121b14a4a80591
13a4c8c113262
144d3c6430153
15273757eba61
hex14d433a433d

1431352001341 has 2 divisors, whose sum is σ = 1431352001342. Its totient is φ = 1431352001340.

The previous prime is 1431352001329. The next prime is 1431352001363. The reversal of 1431352001341 is 1431002531341.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1389958471225 + 41393530116 = 1178965^2 + 203454^2 .

It is a cyclic number.

It is not a de Polignac number, because 1431352001341 - 221 = 1431349904189 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1431352001311) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 715676000670 + 715676000671.

It is an arithmetic number, because the mean of its divisors is an integer number (715676000671).

Almost surely, 21431352001341 is an apocalyptic number.

It is an amenable number.

1431352001341 is a deficient number, since it is larger than the sum of its proper divisors (1).

1431352001341 is an equidigital number, since it uses as much as digits as its factorization.

1431352001341 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 4320, while the sum is 28.

Adding to 1431352001341 its reverse (1431002531341), we get a palindrome (2862354532682).

The spelling of 1431352001341 in words is "one trillion, four hundred thirty-one billion, three hundred fifty-two million, one thousand, three hundred forty-one".