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14313541403 = 72044791629
BaseRepresentation
bin11010101010010011…
…10100111100011011
31100221112110020112002
431111021310330123
5213303231311103
610324152511215
71014463044260
oct152511647433
940845406462
1014313541403
116085691567
1229356ab50b
13147156b435
1499adb3267
1558b919488
hex355274f1b

14313541403 has 4 divisors (see below), whose sum is σ = 16358333040. Its totient is φ = 12268749768.

The previous prime is 14313541393. The next prime is 14313541409. The reversal of 14313541403 is 30414531341.

It is a happy number.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 14313541403 - 24 = 14313541387 is a prime.

It is not an unprimeable number, because it can be changed into a prime (14313541409) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1022395808 + ... + 1022395821.

It is an arithmetic number, because the mean of its divisors is an integer number (4089583260).

Almost surely, 214313541403 is an apocalyptic number.

14313541403 is a deficient number, since it is larger than the sum of its proper divisors (2044791637).

14313541403 is an equidigital number, since it uses as much as digits as its factorization.

14313541403 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2044791636.

The product of its (nonzero) digits is 8640, while the sum is 29.

The spelling of 14313541403 in words is "fourteen billion, three hundred thirteen million, five hundred forty-one thousand, four hundred three".

Divisors: 1 7 2044791629 14313541403