Base | Representation |
---|---|
bin | 11010101010010111… |
… | …01101101111001011 |
3 | 1100221120101101012211 |
4 | 31111023231233023 |
5 | 213303343124141 |
6 | 10324211245551 |
7 | 1014500204611 |
oct | 152513555713 |
9 | 40846341184 |
10 | 14314036171 |
11 | 608599a266 |
12 | 29358a98b7 |
13 | 14716b26b6 |
14 | 99b0a16b1 |
15 | 58b9b5d81 |
hex | 3552edbcb |
14314036171 has 4 divisors (see below), whose sum is σ = 14314277512. Its totient is φ = 14313794832.
The previous prime is 14314036157. The next prime is 14314036189. The reversal of 14314036171 is 17163041341.
It is a happy number.
It is a semiprime because it is the product of two primes, and also a brilliant number, because the two primes have the same length, and also an emirpimes, since its reverse is a distinct semiprime: 17163041341 = 36821 ⋅466121.
It is a cyclic number.
It is not a de Polignac number, because 14314036171 - 213 = 14314027979 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (14314036111) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 36751 + ... + 173143.
It is an arithmetic number, because the mean of its divisors is an integer number (3578569378).
Almost surely, 214314036171 is an apocalyptic number.
14314036171 is a deficient number, since it is larger than the sum of its proper divisors (241341).
14314036171 is a wasteful number, since it uses less digits than its factorization.
14314036171 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 241340.
The product of its (nonzero) digits is 6048, while the sum is 31.
The spelling of 14314036171 in words is "fourteen billion, three hundred fourteen million, thirty-six thousand, one hundred seventy-one".
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