14314301601443 has 4 divisors (see below), whose sum is σ = 14440976836968. Its totient is φ = 14187626365920.

The previous prime is 14314301601433. The next prime is 14314301601461. The reversal of 14314301601443 is 34410610341341.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-14314301601443 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (14314301601433) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 63337617593 + ... + 63337617818.

It is an arithmetic number, because the mean of its divisors is an integer number (3610244209242).

Almost surely, 2^{14314301601443} is an apocalyptic number.

14314301601443 is a deficient number, since it is larger than the sum of its proper divisors (126675235525).

14314301601443 is a wasteful number, since it uses less digits than its factorization.

14314301601443 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 126675235524.

The product of its (nonzero) digits is 41472, while the sum is 35.

Adding to 14314301601443 its reverse (34410610341341), we get a palindrome (48724911942784).

The spelling of 14314301601443 in words is "fourteen trillion, three hundred fourteen billion, three hundred one million, six hundred one thousand, four hundred forty-three".