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14314311344301 = 321563221278909
BaseRepresentation
bin1101000001001100111101…
…1100010110000010101101
31212200102201222011121011120
43100103033130112002231
53334011202201004201
650235523122011153
73005113656606663
oct320231734260255
955612658147146
1014314311344301
114619735642761
121732261aa6ab9
137caaaba31c07
14376b60170c33
1519c534be0536
hexd04cf7160ad

14314311344301 has 8 divisors (see below), whose sum is σ = 19086633660960. Its totient is φ = 9542431628592.

The previous prime is 14314311344251. The next prime is 14314311344317. The reversal of 14314311344301 is 10344311341341.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 14314311344301 - 26 = 14314311344237 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (14314311344351) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 110574766 + ... + 110704143.

It is an arithmetic number, because the mean of its divisors is an integer number (2385829207620).

Almost surely, 214314311344301 is an apocalyptic number.

It is an amenable number.

14314311344301 is a deficient number, since it is larger than the sum of its proper divisors (4772322316659).

14314311344301 is a wasteful number, since it uses less digits than its factorization.

14314311344301 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 221300475.

The product of its (nonzero) digits is 20736, while the sum is 33.

Adding to 14314311344301 its reverse (10344311341341), we get a palindrome (24658622685642).

The spelling of 14314311344301 in words is "fourteen trillion, three hundred fourteen billion, three hundred eleven million, three hundred forty-four thousand, three hundred one".

Divisors: 1 3 21563 64689 221278909 663836727 4771437114767 14314311344301