Base | Representation |
---|---|
bin | 10100110101000111111… |
… | …100110001000011001101 |
3 | 12001211202220101021120221 |
4 | 110311013330301003031 |
5 | 141423032343041303 |
6 | 3013331310511341 |
7 | 205263125425132 |
oct | 24650774610315 |
9 | 5054686337527 |
10 | 1431431221453 |
11 | 502080675172 |
12 | 1b1507505551 |
13 | a4ca265c66c |
14 | 4d3d2b72589 |
15 | 2737c7494bd |
hex | 14d47f310cd |
1431431221453 has 2 divisors, whose sum is σ = 1431431221454. Its totient is φ = 1431431221452.
The previous prime is 1431431221361. The next prime is 1431431221463. The reversal of 1431431221453 is 3541221341341.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1373051963529 + 58379257924 = 1171773^2 + 241618^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1431431221453 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1431431221463) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 715715610726 + 715715610727.
It is an arithmetic number, because the mean of its divisors is an integer number (715715610727).
Almost surely, 21431431221453 is an apocalyptic number.
It is an amenable number.
1431431221453 is a deficient number, since it is larger than the sum of its proper divisors (1).
1431431221453 is an equidigital number, since it uses as much as digits as its factorization.
1431431221453 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 34560, while the sum is 34.
Adding to 1431431221453 its reverse (3541221341341), we get a palindrome (4972652562794).
The spelling of 1431431221453 in words is "one trillion, four hundred thirty-one billion, four hundred thirty-one million, two hundred twenty-one thousand, four hundred fifty-three".
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