14314320440403 has 8 divisors (see below), whose sum is σ = 20090274302400. Its totient is φ = 9040623436008.

The previous prime is 14314320440389. The next prime is 14314320440461. The reversal of 14314320440403 is 30404402341341.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 14314320440403 - 2⁹ = 14314320439891 is a prime.

It is not an unprimeable number, because it can be changed into a prime (14314320441403) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 125564214333 + ... + 125564214446.

It is an arithmetic number, because the mean of its divisors is an integer number (2511284287800).

Almost surely, 2^{14314320440403} is an apocalyptic number.

14314320440403 is a deficient number, since it is larger than the sum of its proper divisors (5775953861997).

14314320440403 is a wasteful number, since it uses less digits than its factorization.

14314320440403 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 251128428801.

The product of its (nonzero) digits is 55296, while the sum is 33.

Adding to 14314320440403 its reverse (30404402341341), we get a palindrome (44718722781744).

The spelling of 14314320440403 in words is "fourteen trillion, three hundred fourteen billion, three hundred twenty million, four hundred forty thousand, four hundred three".