Base | Representation |
---|---|
bin | 11010101010011010… |
… | …01101111010100001 |
3 | 1100221121010101121021 |
4 | 31111031031322201 |
5 | 213303443230423 |
6 | 10324223525441 |
7 | 1014503435254 |
oct | 152515157241 |
9 | 40847111537 |
10 | 14314430113 |
11 | 6086139235 |
12 | 2935a59881 |
13 | 14717bcab9 |
14 | 99b16509b |
15 | 58ba4295d |
hex | 35534dea1 |
14314430113 has 2 divisors, whose sum is σ = 14314430114. Its totient is φ = 14314430112.
The previous prime is 14314430087. The next prime is 14314430153. The reversal of 14314430113 is 31103441341.
It is a happy number.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 14311815424 + 2614689 = 119632^2 + 1617^2 .
It is a cyclic number.
It is not a de Polignac number, because 14314430113 - 213 = 14314421921 is a prime.
It is a super-2 number, since 2×143144301132 (a number of 21 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (14314430153) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7157215056 + 7157215057.
It is an arithmetic number, because the mean of its divisors is an integer number (7157215057).
Almost surely, 214314430113 is an apocalyptic number.
It is an amenable number.
14314430113 is a deficient number, since it is larger than the sum of its proper divisors (1).
14314430113 is an equidigital number, since it uses as much as digits as its factorization.
14314430113 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1728, while the sum is 25.
Adding to 14314430113 its reverse (31103441341), we get a palindrome (45417871454).
The spelling of 14314430113 in words is "fourteen billion, three hundred fourteen million, four hundred thirty thousand, one hundred thirteen".
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