14314543010101 has 2 divisors, whose sum is σ = 14314543010102. Its totient is φ = 14314543010100.

The previous prime is 14314543010023. The next prime is 14314543010113. The reversal of 14314543010101 is 10101034541341.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 13107513384900 + 1207029625201 = 3620430^2 + 1098649^2 .

It is an emirp because it is prime and its reverse (10101034541341) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 14314543010101 - 2¹³ = 14314543001909 is a prime.

It is a super-3 number, since 3×14314543010101³ (a number of 40 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a self number, because there is not a number n which added to its sum of digits gives 14314543010101.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (14314543010501) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7157271505050 + 7157271505051.

It is an arithmetic number, because the mean of its divisors is an integer number (7157271505051).

Almost surely, 2^{14314543010101} is an apocalyptic number.

It is an amenable number.

14314543010101 is a deficient number, since it is larger than the sum of its proper divisors (1).

14314543010101 is an equidigital number, since it uses as much as digits as its factorization.

14314543010101 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2880, while the sum is 28.

Adding to 14314543010101 its reverse (10101034541341), we get a palindrome (24415577551442).

The spelling of 14314543010101 in words is "fourteen trillion, three hundred fourteen billion, five hundred forty-three million, ten thousand, one hundred one".