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143150442151 is a prime number
BaseRepresentation
bin1000010101010001101…
…1100110011010100111
3111200111101210220220211
42011110123212122213
54321133003122101
6145432402440251
713225254452563
oct2052433463247
9450441726824
10143150442151
1155789768a42
12238b0963087
131066449b752
146cddbd66a3
153acc5d0c51
hex21546e66a7

143150442151 has 2 divisors, whose sum is σ = 143150442152. Its totient is φ = 143150442150.

The previous prime is 143150442137. The next prime is 143150442157. The reversal of 143150442151 is 151244051341.

143150442151 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 143150442151 - 215 = 143150409383 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (143150442157) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 71575221075 + 71575221076.

It is an arithmetic number, because the mean of its divisors is an integer number (71575221076).

Almost surely, 2143150442151 is an apocalyptic number.

143150442151 is a deficient number, since it is larger than the sum of its proper divisors (1).

143150442151 is an equidigital number, since it uses as much as digits as its factorization.

143150442151 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 9600, while the sum is 31.

Adding to 143150442151 its reverse (151244051341), we get a palindrome (294394493492).

The spelling of 143150442151 in words is "one hundred forty-three billion, one hundred fifty million, four hundred forty-two thousand, one hundred fifty-one".