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143172997633 is a prime number
BaseRepresentation
bin1000010101010111000…
…1101001001000000001
3111200112222020212020001
42011111301221020001
54321204241411013
6145434530120001
713225650254161
oct2052561511001
9450488225201
10143172997633
11557a0474236
12238b8420001
13106690680a3
146d02bc85a1
153ace588ddd
hex2155c69201

143172997633 has 2 divisors, whose sum is σ = 143172997634. Its totient is φ = 143172997632.

The previous prime is 143172997631. The next prime is 143172997657. The reversal of 143172997633 is 336799271341.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 75577157569 + 67595840064 = 274913^2 + 259992^2 .

It is a cyclic number.

It is not a de Polignac number, because 143172997633 - 21 = 143172997631 is a prime.

Together with 143172997631, it forms a pair of twin primes.

It is not a weakly prime, because it can be changed into another prime (143172997631) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 71586498816 + 71586498817.

It is an arithmetic number, because the mean of its divisors is an integer number (71586498817).

Almost surely, 2143172997633 is an apocalyptic number.

It is an amenable number.

143172997633 is a deficient number, since it is larger than the sum of its proper divisors (1).

143172997633 is an equidigital number, since it uses as much as digits as its factorization.

143172997633 is an evil number, because the sum of its binary digits is even.

The product of its digits is 5143824, while the sum is 55.

It can be divided in two parts, 143172 and 997633, that added together give a triangular number (1140805 = T1510).

The spelling of 143172997633 in words is "one hundred forty-three billion, one hundred seventy-two million, nine hundred ninety-seven thousand, six hundred thirty-three".