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14318444113 = 18797620247
BaseRepresentation
bin11010101010111001…
…00001111001010001
31100221212200022202221
431111130201321101
5213311010202423
610324445541041
71014552524011
oct152534417121
940855608687
1014318444113
11608842aa96
122937274781
131472596b4c
1499b8cbc41
1558c086e5d
hex355721e51

14318444113 has 4 divisors (see below), whose sum is σ = 14326066240. Its totient is φ = 14310821988.

The previous prime is 14318444111. The next prime is 14318444131. The reversal of 14318444113 is 31144481341.

14318444113 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 14318444113 - 21 = 14318444111 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (14318444111) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3808245 + ... + 3812002.

It is an arithmetic number, because the mean of its divisors is an integer number (3581516560).

Almost surely, 214318444113 is an apocalyptic number.

It is an amenable number.

14318444113 is a deficient number, since it is larger than the sum of its proper divisors (7622127).

14318444113 is an equidigital number, since it uses as much as digits as its factorization.

14318444113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 7622126.

The product of its digits is 18432, while the sum is 34.

The spelling of 14318444113 in words is "fourteen billion, three hundred eighteen million, four hundred forty-four thousand, one hundred thirteen".

Divisors: 1 1879 7620247 14318444113