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14318449993 is a prime number
BaseRepresentation
bin11010101010111001…
…00011010101001001
31100221212200121211201
431111130203111021
5213311010344433
610324450024201
71014552550111
oct152534432511
940855617751
1014318449993
116088434451
122937278061
131472599723
1499b8d0041
1558c088a7d
hex355723549

14318449993 has 2 divisors, whose sum is σ = 14318449994. Its totient is φ = 14318449992.

The previous prime is 14318449933. The next prime is 14318449997. The reversal of 14318449993 is 39994481341.

14318449993 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 14313011769 + 5438224 = 119637^2 + 2332^2 .

It is an emirp because it is prime and its reverse (39994481341) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-14318449993 is a prime.

It is not a weakly prime, because it can be changed into another prime (14318449997) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7159224996 + 7159224997.

It is an arithmetic number, because the mean of its divisors is an integer number (7159224997).

Almost surely, 214318449993 is an apocalyptic number.

It is an amenable number.

14318449993 is a deficient number, since it is larger than the sum of its proper divisors (1).

14318449993 is an equidigital number, since it uses as much as digits as its factorization.

14318449993 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 3359232, while the sum is 55.

The spelling of 14318449993 in words is "fourteen billion, three hundred eighteen million, four hundred forty-nine thousand, nine hundred ninety-three".