1432000121 has 4 divisors (see below), whose sum is σ = 1448090100. Its totient is φ = 1415910144.

The previous prime is 1432000091. The next prime is 1432000133. The reversal of 1432000121 is 1210002341.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 1210002341 = 167 ⋅7245523.

It can be written as a sum of positive squares in 2 ways, for example, as 603193600 + 828806521 = 24560^2 + 28789^2 .

It is a cyclic number.

It is not a de Polignac number, because 1432000121 - 2²² = 1427805817 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1432000096 and 1432000105.

It is not an unprimeable number, because it can be changed into a prime (1432000181) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 8044856 + ... + 8045033.

It is an arithmetic number, because the mean of its divisors is an integer number (362022525).

Almost surely, 2^1432000121 is an apocalyptic number.

It is an amenable number.

1432000121 is a deficient number, since it is larger than the sum of its proper divisors (16089979).

1432000121 is an equidigital number, since it uses as much as digits as its factorization.

1432000121 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 16089978.

The product of its (nonzero) digits is 48, while the sum is 14.

The square root of 1432000121 is about 37841.7774556111. Note that the first 3 decimals coincide. The cubic root of 1432000121 is about 1127.1481906558.

Adding to 1432000121 its reverse (1210002341), we get a palindrome (2642002462).

The spelling of 1432000121 in words is "one billion, four hundred thirty-two million, one hundred twenty-one", and thus it is an aban number.