14320111241 has 2 divisors, whose sum is σ = 14320111242. Its totient is φ = 14320111240.

The previous prime is 14320111129. The next prime is 14320111283. The reversal of 14320111241 is 14211102341.

14320111241 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 12994860025 + 1325251216 = 113995^2 + 36404^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-14320111241 is a prime.

It is a super-2 number, since 2×14320111241² (a number of 21 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (14320111291) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7160055620 + 7160055621.

It is an arithmetic number, because the mean of its divisors is an integer number (7160055621).

Almost surely, 2^14320111241 is an apocalyptic number.

It is an amenable number.

14320111241 is a deficient number, since it is larger than the sum of its proper divisors (1).

14320111241 is an equidigital number, since it uses as much as digits as its factorization.

14320111241 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 192, while the sum is 20.

Adding to 14320111241 its reverse (14211102341), we get a palindrome (28531213582).

The spelling of 14320111241 in words is "fourteen billion, three hundred twenty million, one hundred eleven thousand, two hundred forty-one".