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1432012240141 = 7204573177163
BaseRepresentation
bin10100110101101010100…
…101001011010100001101
312001220021101200002101121
4110311222211023110031
5141430230113141031
63013505104040541
7205313412130150
oct24655245132415
95056241602347
101432012240141
115023496390aa
121b164a003151
13a5065b406c2
144d449db7c97
15273b3768011
hex14d6a94b50d

1432012240141 has 4 divisors (see below), whose sum is σ = 1636585417312. Its totient is φ = 1227439062972.

The previous prime is 1432012240133. The next prime is 1432012240201. The reversal of 1432012240141 is 1410422102341.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1432012240141 - 23 = 1432012240133 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1432012340141) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 102286588575 + ... + 102286588588.

It is an arithmetic number, because the mean of its divisors is an integer number (409146354328).

Almost surely, 21432012240141 is an apocalyptic number.

It is an amenable number.

1432012240141 is a deficient number, since it is larger than the sum of its proper divisors (204573177171).

1432012240141 is an equidigital number, since it uses as much as digits as its factorization.

1432012240141 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 204573177170.

The product of its (nonzero) digits is 1536, while the sum is 25.

Adding to 1432012240141 its reverse (1410422102341), we get a palindrome (2842434342482).

The spelling of 1432012240141 in words is "one trillion, four hundred thirty-two billion, twelve million, two hundred forty thousand, one hundred forty-one".

Divisors: 1 7 204573177163 1432012240141