Base | Representation |
---|---|
bin | 10100110101101010100… |
… | …101001011010100001101 |
3 | 12001220021101200002101121 |
4 | 110311222211023110031 |
5 | 141430230113141031 |
6 | 3013505104040541 |
7 | 205313412130150 |
oct | 24655245132415 |
9 | 5056241602347 |
10 | 1432012240141 |
11 | 5023496390aa |
12 | 1b164a003151 |
13 | a5065b406c2 |
14 | 4d449db7c97 |
15 | 273b3768011 |
hex | 14d6a94b50d |
1432012240141 has 4 divisors (see below), whose sum is σ = 1636585417312. Its totient is φ = 1227439062972.
The previous prime is 1432012240133. The next prime is 1432012240201. The reversal of 1432012240141 is 1410422102341.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 1432012240141 - 23 = 1432012240133 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1432012340141) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 102286588575 + ... + 102286588588.
It is an arithmetic number, because the mean of its divisors is an integer number (409146354328).
Almost surely, 21432012240141 is an apocalyptic number.
It is an amenable number.
1432012240141 is a deficient number, since it is larger than the sum of its proper divisors (204573177171).
1432012240141 is an equidigital number, since it uses as much as digits as its factorization.
1432012240141 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 204573177170.
The product of its (nonzero) digits is 1536, while the sum is 25.
Adding to 1432012240141 its reverse (1410422102341), we get a palindrome (2842434342482).
The spelling of 1432012240141 in words is "one trillion, four hundred thirty-two billion, twelve million, two hundred forty thousand, one hundred forty-one".
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