Base | Representation |
---|---|
bin | 10100110101101010100… |
… | …101001011010101001111 |
3 | 12001220021101200002111001 |
4 | 110311222211023111033 |
5 | 141430230113141312 |
6 | 3013505104041131 |
7 | 205313412130303 |
oct | 24655245132517 |
9 | 5056241602431 |
10 | 1432012240207 |
11 | 50234963915a |
12 | 1b164a0031a7 |
13 | a5065b40743 |
14 | 4d449db7d03 |
15 | 273b3768057 |
hex | 14d6a94b54f |
1432012240207 has 2 divisors, whose sum is σ = 1432012240208. Its totient is φ = 1432012240206.
The previous prime is 1432012240201. The next prime is 1432012240247. The reversal of 1432012240207 is 7020422102341.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1432012240207 - 27 = 1432012240079 is a prime.
It is a super-2 number, since 2×14320122402072 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1432012240201) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 716006120103 + 716006120104.
It is an arithmetic number, because the mean of its divisors is an integer number (716006120104).
Almost surely, 21432012240207 is an apocalyptic number.
1432012240207 is a deficient number, since it is larger than the sum of its proper divisors (1).
1432012240207 is an equidigital number, since it uses as much as digits as its factorization.
1432012240207 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 5376, while the sum is 28.
Adding to 1432012240207 its reverse (7020422102341), we get a palindrome (8452434342548).
The spelling of 1432012240207 in words is "one trillion, four hundred thirty-two billion, twelve million, two hundred forty thousand, two hundred seven".
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