Base | Representation |
---|---|
bin | 10100110101101010100… |
… | …101110010101000111011 |
3 | 12001220021101222021100011 |
4 | 110311222211302220323 |
5 | 141430230133314321 |
6 | 3013505111322351 |
7 | 205313413400560 |
oct | 24655245625073 |
9 | 5056241867304 |
10 | 1432012401211 |
11 | 502349739117 |
12 | 1b164a0803b7 |
13 | a5065b98b02 |
14 | 4d44a01a867 |
15 | 273b379aae1 |
hex | 14d6a972a3b |
1432012401211 has 16 divisors (see below), whose sum is σ = 1643968548288. Its totient is φ = 1221905664000.
The previous prime is 1432012401173. The next prime is 1432012401271. The reversal of 1432012401211 is 1121042102341.
It is not a de Polignac number, because 1432012401211 - 215 = 1432012368443 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (1432012401271) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 4573761 + ... + 4876813.
It is an arithmetic number, because the mean of its divisors is an integer number (102748034268).
Almost surely, 21432012401211 is an apocalyptic number.
1432012401211 is a deficient number, since it is larger than the sum of its proper divisors (211956147077).
1432012401211 is a wasteful number, since it uses less digits than its factorization.
1432012401211 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 306102.
The product of its (nonzero) digits is 384, while the sum is 22.
Adding to 1432012401211 its reverse (1121042102341), we get a palindrome (2553054503552).
The spelling of 1432012401211 in words is "one trillion, four hundred thirty-two billion, twelve million, four hundred one thousand, two hundred eleven".
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