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1432012401173 is a prime number
BaseRepresentation
bin10100110101101010100…
…101110010101000010101
312001220021101222021021202
4110311222211302220111
5141430230133314143
63013505111322245
7205313413400504
oct24655245625025
95056241867252
101432012401173
11502349739092
121b164a080385
13a5065b98aa3
144d44a01a83b
15273b379aab8
hex14d6a972a15

1432012401173 has 2 divisors, whose sum is σ = 1432012401174. Its totient is φ = 1432012401172.

The previous prime is 1432012401143. The next prime is 1432012401271. The reversal of 1432012401173 is 3711042102341.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1083083548369 + 348928852804 = 1040713^2 + 590702^2 .

It is a cyclic number.

It is not a de Polignac number, because 1432012401173 - 218 = 1432012139029 is a prime.

It is a super-2 number, since 2×14320124011732 (a number of 25 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1432012401143) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 716006200586 + 716006200587.

It is an arithmetic number, because the mean of its divisors is an integer number (716006200587).

Almost surely, 21432012401173 is an apocalyptic number.

It is an amenable number.

1432012401173 is a deficient number, since it is larger than the sum of its proper divisors (1).

1432012401173 is an equidigital number, since it uses as much as digits as its factorization.

1432012401173 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 4032, while the sum is 29.

The spelling of 1432012401173 in words is "one trillion, four hundred thirty-two billion, twelve million, four hundred one thousand, one hundred seventy-three".