Base | Representation |
---|---|
bin | 10100110101101010100… |
… | …101110010101001110111 |
3 | 12001220021101222021102101 |
4 | 110311222211302221313 |
5 | 141430230133320041 |
6 | 3013505111322531 |
7 | 205313413401004 |
oct | 24655245625167 |
9 | 5056241867371 |
10 | 1432012401271 |
11 | 502349739171 |
12 | 1b164a080447 |
13 | a5065b98b4a |
14 | 4d44a01a8ab |
15 | 273b379ab31 |
hex | 14d6a972a77 |
1432012401271 has 2 divisors, whose sum is σ = 1432012401272. Its totient is φ = 1432012401270.
The previous prime is 1432012401173. The next prime is 1432012401293. The reversal of 1432012401271 is 1721042102341.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1432012401271 - 27 = 1432012401143 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1432012408271) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 716006200635 + 716006200636.
It is an arithmetic number, because the mean of its divisors is an integer number (716006200636).
Almost surely, 21432012401271 is an apocalyptic number.
1432012401271 is a deficient number, since it is larger than the sum of its proper divisors (1).
1432012401271 is an equidigital number, since it uses as much as digits as its factorization.
1432012401271 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2688, while the sum is 28.
The spelling of 1432012401271 in words is "one trillion, four hundred thirty-two billion, twelve million, four hundred one thousand, two hundred seventy-one".
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