143201240131 has 4 divisors (see below), whose sum is σ = 143293451112. Its totient is φ = 143109029152.

The previous prime is 143201240099. The next prime is 143201240153. The reversal of 143201240131 is 131042102341.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 143201240131 - 2⁵ = 143201240099 is a prime.

It is a super-2 number, since 2×143201240131² (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (143201250131) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 46103161 + ... + 46106266.

It is an arithmetic number, because the mean of its divisors is an integer number (35823362778).

Almost surely, 2^143201240131 is an apocalyptic number.

143201240131 is a deficient number, since it is larger than the sum of its proper divisors (92210981).

143201240131 is an equidigital number, since it uses as much as digits as its factorization.

143201240131 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 92210980.

The product of its (nonzero) digits is 576, while the sum is 22.

Adding to 143201240131 its reverse (131042102341), we get a palindrome (274243342472).

The spelling of 143201240131 in words is "one hundred forty-three billion, two hundred one million, two hundred forty thousand, one hundred thirty-one".