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143201321 is a prime number
BaseRepresentation
bin10001000100100…
…01010000101001
3100222110101021122
420202101100221
5243124420241
622113145025
73356122364
oct1042212051
9328411248
10143201321
11739192aa
123bb5b175
132388b513
14150390db
15c88a04b
hex8891429

143201321 has 2 divisors, whose sum is σ = 143201322. Its totient is φ = 143201320.

The previous prime is 143201293. The next prime is 143201329. The reversal of 143201321 is 123102341.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 120209296 + 22992025 = 10964^2 + 4795^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-143201321 is a prime.

It is a super-2 number, since 2×1432013212 = 41013236672290082, which contains 22 as substring.

It is a Chen prime.

It is a self number, because there is not a number n which added to its sum of digits gives 143201321.

It is not a weakly prime, because it can be changed into another prime (143201329) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 71600660 + 71600661.

It is an arithmetic number, because the mean of its divisors is an integer number (71600661).

Almost surely, 2143201321 is an apocalyptic number.

It is an amenable number.

143201321 is a deficient number, since it is larger than the sum of its proper divisors (1).

143201321 is an equidigital number, since it uses as much as digits as its factorization.

143201321 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 144, while the sum is 17.

The square root of 143201321 is about 11966.6754363942. The cubic root of 143201321 is about 523.1774395582.

Adding to 143201321 its reverse (123102341), we get a palindrome (266303662).

The spelling of 143201321 in words is "one hundred forty-three million, two hundred one thousand, three hundred twenty-one".