1432141240131 has 40 divisors (see below), whose sum is σ = 2445337574240. Its totient is φ = 818252088192.

The previous prime is 1432141240081. The next prime is 1432141240141. The reversal of 1432141240131 is 1310421412341.

It is a happy number.

1432141240131 is a `hidden beast` number, since 1 + 4 + 3 + 214 + 12 + 401 + 31 = 666.

It is not a de Polignac number, because 1432141240131 - 2¹⁰ = 1432141239107 is a prime.

It is a super-2 number, since 2×1432141240131² (a number of 25 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (27).

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1432141240095 and 1432141240104.

It is not an unprimeable number, because it can be changed into a prime (1432141240141) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 39 ways as a sum of consecutive naturals, for example, 3971415 + ... + 4316991.

It is an arithmetic number, because the mean of its divisors is an integer number (61133439356).

Almost surely, 2^{1432141240131} is an apocalyptic number.

1432141240131 is a deficient number, since it is larger than the sum of its proper divisors (1013196334109).

1432141240131 is an equidigital number, since it uses as much as digits as its factorization.

1432141240131 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 352905 (or 352896 counting only the distinct ones).

The product of its (nonzero) digits is 2304, while the sum is 27.

Adding to 1432141240131 its reverse (1310421412341), we get a palindrome (2742562652472).

The spelling of 1432141240131 in words is "one trillion, four hundred thirty-two billion, one hundred forty-one million, two hundred forty thousand, one hundred thirty-one".