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14322011213327 is a prime number
BaseRepresentation
bin1101000001101001101001…
…1001000000111000001111
31212201011121120211110202212
43100122122121000320033
53334122434332311302
650243235140541035
73005505534453506
oct320323231007017
955634546743685
1014322011213327
114621a26a57284
1217338506b177b
137cb73802c72c
14377290a2d83d
1519c835ba3052
hexd069a640e0f

14322011213327 has 2 divisors, whose sum is σ = 14322011213328. Its totient is φ = 14322011213326.

The previous prime is 14322011213249. The next prime is 14322011213333. The reversal of 14322011213327 is 72331211022341.

It is a strong prime.

It is an emirp because it is prime and its reverse (72331211022341) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 14322011213327 - 210 = 14322011212303 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 14322011213293 and 14322011213302.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (14322011210327) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7161005606663 + 7161005606664.

It is an arithmetic number, because the mean of its divisors is an integer number (7161005606664).

Almost surely, 214322011213327 is an apocalyptic number.

14322011213327 is a deficient number, since it is larger than the sum of its proper divisors (1).

14322011213327 is an equidigital number, since it uses as much as digits as its factorization.

14322011213327 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 12096, while the sum is 32.

Adding to 14322011213327 its reverse (72331211022341), we get a palindrome (86653222235668).

The spelling of 14322011213327 in words is "fourteen trillion, three hundred twenty-two billion, eleven million, two hundred thirteen thousand, three hundred twenty-seven".