Base | Representation |
---|---|
bin | 10100110101110110000… |
… | …000110001000101101001 |
3 | 12001220202202112121210220 |
4 | 110311312000301011221 |
5 | 141431123212201441 |
6 | 3013540114400253 |
7 | 205321231216245 |
oct | 24656600610551 |
9 | 5056682477726 |
10 | 1432204022121 |
11 | 502437918804 |
12 | 1b16a2290089 |
13 | a50967ab272 |
14 | 4d46765b425 |
15 | 273c54ec466 |
hex | 14d76031169 |
1432204022121 has 24 divisors (see below), whose sum is σ = 2048440123584. Its totient is φ = 889721180640.
The previous prime is 1432204022071. The next prime is 1432204022203. The reversal of 1432204022121 is 1212204022341.
It is not a de Polignac number, because 1432204022121 - 210 = 1432204021097 is a prime.
It is a Curzon number.
It is a junction number, because it is equal to n+sod(n) for n = 1432204022091 and 1432204022100.
It is not an unprimeable number, because it can be changed into a prime (1432204021121) by changing a digit.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 10773621 + ... + 10905746.
It is an arithmetic number, because the mean of its divisors is an integer number (85351671816).
Almost surely, 21432204022121 is an apocalyptic number.
It is an amenable number.
1432204022121 is a deficient number, since it is larger than the sum of its proper divisors (616236101463).
1432204022121 is a wasteful number, since it uses less digits than its factorization.
1432204022121 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 21679469 (or 21679450 counting only the distinct ones).
The product of its (nonzero) digits is 1536, while the sum is 24.
Adding to 1432204022121 its reverse (1212204022341), we get a palindrome (2644408044462).
The spelling of 1432204022121 in words is "one trillion, four hundred thirty-two billion, two hundred four million, twenty-two thousand, one hundred twenty-one".
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