143220440204041 has 4 divisors (see below), whose sum is σ = 143220592539972. Its totient is φ = 143220287868112.

The previous prime is 143220440204011. The next prime is 143220440204071. The reversal of 143220440204041 is 140402044022341.

It is a happy number.

It is a semiprime because it is the product of two primes.

It is an interprime number because it is at equal distance from previous prime (143220440204011) and next prime (143220440204071).

It can be written as a sum of positive squares in 2 ways, for example, as 6325853765625 + 136894586438416 = 2515125^2 + 11700196^2 .

It is a cyclic number.

It is not a de Polignac number, because 143220440204041 - 2¹³ = 143220440195849 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 143220440203994 and 143220440204012.

It is not an unprimeable number, because it can be changed into a prime (143220440204011) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 74748910 + ... + 76640983.

It is an arithmetic number, because the mean of its divisors is an integer number (35805148134993).

Almost surely, 2^{143220440204041} is an apocalyptic number.

It is an amenable number.

143220440204041 is a deficient number, since it is larger than the sum of its proper divisors (152335931).

143220440204041 is an equidigital number, since it uses as much as digits as its factorization.

143220440204041 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 152335930.

The product of its (nonzero) digits is 24576, while the sum is 31.

Adding to 143220440204041 its reverse (140402044022341), we get a palindrome (283622484226382).

The spelling of 143220440204041 in words is "one hundred forty-three trillion, two hundred twenty billion, four hundred forty million, two hundred four thousand, forty-one".