143221054242401 has 2 divisors, whose sum is σ = 143221054242402. Its totient is φ = 143221054242400.

The previous prime is 143221054242391. The next prime is 143221054242403. The reversal of 143221054242401 is 104242450122341.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 98368231541776 + 44852822700625 = 9918076^2 + 6697225^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-143221054242401 is a prime.

Together with 143221054242403, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (143221054242403) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 71610527121200 + 71610527121201.

It is an arithmetic number, because the mean of its divisors is an integer number (71610527121201).

Almost surely, 2^{143221054242401} is an apocalyptic number.

It is an amenable number.

143221054242401 is a deficient number, since it is larger than the sum of its proper divisors (1).

143221054242401 is an equidigital number, since it uses as much as digits as its factorization.

143221054242401 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 61440, while the sum is 35.

The spelling of 143221054242401 in words is "one hundred forty-three trillion, two hundred twenty-one billion, fifty-four million, two hundred forty-two thousand, four hundred one".