Base | Representation |
---|---|
bin | 1101000001101010011001… |
… | …0001001101100111111011 |
3 | 1212201012010110211000210111 |
4 | 3100122212101031213323 |
5 | 3334123341341314341 |
6 | 50243311020125151 |
7 | 3005513504356531 |
oct | 320324621154773 |
9 | 55635113730714 |
10 | 14322210494971 |
11 | 4622019499555 |
12 | 17338a73967b7 |
13 | 7cb76a3c4a72 |
14 | 3772ad2a6151 |
15 | 19c848419681 |
hex | d06a644d9fb |
14322210494971 has 2 divisors, whose sum is σ = 14322210494972. Its totient is φ = 14322210494970.
The previous prime is 14322210494951. The next prime is 14322210494983. The reversal of 14322210494971 is 17949401222341.
It is a strong prime.
It is an emirp because it is prime and its reverse (17949401222341) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 14322210494971 - 217 = 14322210363899 is a prime.
It is not a weakly prime, because it can be changed into another prime (14322210494951) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7161105247485 + 7161105247486.
It is an arithmetic number, because the mean of its divisors is an integer number (7161105247486).
Almost surely, 214322210494971 is an apocalyptic number.
14322210494971 is a deficient number, since it is larger than the sum of its proper divisors (1).
14322210494971 is an equidigital number, since it uses as much as digits as its factorization.
14322210494971 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 870912, while the sum is 49.
The spelling of 14322210494971 in words is "fourteen trillion, three hundred twenty-two billion, two hundred ten million, four hundred ninety-four thousand, nine hundred seventy-one".
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