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1432242201307 is a prime number
BaseRepresentation
bin10100110101111000010…
…010011010001011011011
312001220212102101022210211
4110311320102122023123
5141431213000420212
63013544000551551
7205322203561651
oct24657022321333
95056772338724
101432242201307
11502457425355
121b16b30225b7
13a50a16880b8
144d46c758dd1
15273c8a3e9a7
hex14d7849a2db

1432242201307 has 2 divisors, whose sum is σ = 1432242201308. Its totient is φ = 1432242201306.

The previous prime is 1432242201293. The next prime is 1432242201317. The reversal of 1432242201307 is 7031022422341.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 1432242201307 - 27 = 1432242201179 is a prime.

It is a super-2 number, since 2×14322422013072 (a number of 25 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (1432242201317) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 716121100653 + 716121100654.

It is an arithmetic number, because the mean of its divisors is an integer number (716121100654).

Almost surely, 21432242201307 is an apocalyptic number.

1432242201307 is a deficient number, since it is larger than the sum of its proper divisors (1).

1432242201307 is an equidigital number, since it uses as much as digits as its factorization.

1432242201307 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 16128, while the sum is 31.

Adding to 1432242201307 its reverse (7031022422341), we get a palindrome (8463264623648).

The spelling of 1432242201307 in words is "one trillion, four hundred thirty-two billion, two hundred forty-two million, two hundred one thousand, three hundred seven".