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143224460024117 is a prime number
BaseRepresentation
bin100000100100001100001011…
…000100000001100100110101
3200210010010100212122110200212
4200210030023010001210311
5122233042143231232432
61224340224131515205
742111424431206633
oct4044141304014465
9623103325573625
10143224460024117
11416aa17491428a
1214091a39a58b05
1361bc015c55304
14275215aa4c353
1511858e47642b2
hex82430b101935

143224460024117 has 2 divisors, whose sum is σ = 143224460024118. Its totient is φ = 143224460024116.

The previous prime is 143224460023999. The next prime is 143224460024203. The reversal of 143224460024117 is 711420064422341.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 140482965207601 + 2741494816516 = 11852551^2 + 1655746^2 .

It is a cyclic number.

It is not a de Polignac number, because 143224460024117 - 218 = 143224459761973 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (143224460024417) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 71612230012058 + 71612230012059.

It is an arithmetic number, because the mean of its divisors is an integer number (71612230012059).

Almost surely, 2143224460024117 is an apocalyptic number.

It is an amenable number.

143224460024117 is a deficient number, since it is larger than the sum of its proper divisors (1).

143224460024117 is an equidigital number, since it uses as much as digits as its factorization.

143224460024117 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 258048, while the sum is 41.

The spelling of 143224460024117 in words is "one hundred forty-three trillion, two hundred twenty-four billion, four hundred sixty million, twenty-four thousand, one hundred seventeen".