Base | Representation |
---|---|
bin | 100000100100001100001011… |
… | …000100000001100100110101 |
3 | 200210010010100212122110200212 |
4 | 200210030023010001210311 |
5 | 122233042143231232432 |
6 | 1224340224131515205 |
7 | 42111424431206633 |
oct | 4044141304014465 |
9 | 623103325573625 |
10 | 143224460024117 |
11 | 416aa17491428a |
12 | 14091a39a58b05 |
13 | 61bc015c55304 |
14 | 275215aa4c353 |
15 | 11858e47642b2 |
hex | 82430b101935 |
143224460024117 has 2 divisors, whose sum is σ = 143224460024118. Its totient is φ = 143224460024116.
The previous prime is 143224460023999. The next prime is 143224460024203. The reversal of 143224460024117 is 711420064422341.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 140482965207601 + 2741494816516 = 11852551^2 + 1655746^2 .
It is a cyclic number.
It is not a de Polignac number, because 143224460024117 - 218 = 143224459761973 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (143224460024417) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 71612230012058 + 71612230012059.
It is an arithmetic number, because the mean of its divisors is an integer number (71612230012059).
Almost surely, 2143224460024117 is an apocalyptic number.
It is an amenable number.
143224460024117 is a deficient number, since it is larger than the sum of its proper divisors (1).
143224460024117 is an equidigital number, since it uses as much as digits as its factorization.
143224460024117 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 258048, while the sum is 41.
The spelling of 143224460024117 in words is "one hundred forty-three trillion, two hundred twenty-four billion, four hundred sixty million, twenty-four thousand, one hundred seventeen".
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